Question 436845
{{{H(H^(-1)(-2)) = -2 = 2*(H^(-1)(-2))^3 + 5*(H^(-1)(-2)) - 2}}}
==> {{{2*(H^(-1)(-2))^3 + 5*(H^(-1)(-2)) = 0}}}
==> {{{(H^(-1)(-2))(2(H^(-1)(-2))^2 + 5) = 0}}}
==> {{{H^(-1)(-2) = 0}}}
***Think of it this way:  H(0) = -2, and so {{{0 = H^(-1)(-2)}}}.