Question 45457
{{{log(8,(x^2 + 1)) = y}}}
{{{(x^2 + 1) = 8^y}}}
{{{log(e,(x^2 + 1)) = log(e,8^y)}}}
{{{log(e,(x^2 + 1)) = y*log(e,8)}}}
{{{log(e,(x^2 + 1))/log(e,8) = y}}}
{{{log(e,x)}}} is that same as {{{ln(x)}}}