Question 45457
Rewrite log8 (x^2 + 1) in terms of natural logarithms. 
The 8 being the base (small 8 at the bottom of the g)
I understand natural logarithms is LN, right? So I turnerd it into
8 to the power of y = x squared + 1.

The log law is log(base a)b = [log(base c)b]/[log(base c)a]
The base c may be any positive number except c=1.

So log (base 8)(x^2+1) can be written as [ln(x^2+1)]/[ln8]

Cheers,
Stan H.