Question 436693
type in exponential notation with positive exponents: 
((49b^2)/(4b^2-8b+4)) * ((4b-4)/7b)
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You can cancel 49b^2 with 7b
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[7b/(4(b^2-2b+1)]*(4(b-1)/1)
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Factor:
=[7b/4(b-1)^2]*[4(b-1)/1]
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Cancel (b-1)  and 4 to get:
= [7b/1][(b-1)/1]
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= 7b(b-1)
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Cheers,
Stan H.
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