Question 436570
 Combine 
3log(base2)x + 1(over)2log(base8)x - 2log(base2)(x+1) 
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2log2(x) + (1/2)log8(x) - 2log2(x+1)
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Note log8(x) = (1/3)log(x)
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log2(x^2) + (1/6)log(x) -log2(x+1)^2
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= log2[(x^2*x^(1/6)/(x+1)^2]
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= log2[x^(7/6)/(x+1)^2]
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Cheers,
Stan H.