Question 436571
solve for x 
m = a(over)1+be^x
-----
m = a/(1+be^x)
---
1+be^x = a/m
-----
be^x = (a/m)-1
---
e^x = [(a/m)-1]/b
---
Take the natural log to get:
x = ln[(a/m)-1)/b]
========================
Cheers,
Stan H.