Question 436546
A rare isotope of a nuclear material is very unstable, decaying at a rate of 12% each second. Find how much isotope remains 10 seconds after 4 grams of the isotope is created. Use y=4(2.7)^0.12t, where t represents time in seconds.. 
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In the given equation: (I think you need a negative sign)
y=4(2.7)^-0.12t
y is the amount (grams) left
after t (seconds)
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simply replace t with 10 and equate:
y=4(2.7)^-0.12t
y=4(2.7)^-0.12(10)
y=4(2.7)^-1.2
y=4(0.30364)
y=1.2 grams