Question 436360
|(2/3)x -1| - 2 >1/3 
The solution should be:
(-infinity, -2) U (5,infinity) 
I a getting 5 right but I cant figute out how to get -2. 
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|(2/3)x -1| - 2 >1/3 
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Add 2 to both sides to get:
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|(2/3)x -1| > 2 + 1/3
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|(2/3)x -1| > 7/3
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(2/3)x-1<-7/3 or (2/3)x-1>7/3
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(2/3)x < -4/3 or (2/3)x > 10/3
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x < -2 or x > 5
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Solution:
(-inf,-2)U(5,+inf)
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Cheers,
Stan H.
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