Question 436332
Soybean is 18% protein
Cornmeal is 9% protein
How many lbs of each should be mixed together to get 360-lb mixture that is 12% protein?
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Equations:
Quantity Eq: s + c = 360 lb
Protein Eq:0.18s+0.09c = 0.12(360)
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Multiply thru the 1st by 18
Multiply thru the 2nd by 100
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18s + 18c = 18*360
18x +  9c = 12*360
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Subtract and solve for "c":
9c = 6*360
c = (2/3)360
c = 240 lb. (amt. of cornmeal needed)
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Solve for "s":
s + c = 360
s + 240 = 360
s = 120 lb (amt of soybean needed)
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Cheers,
Stan H.
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