Question 436178
Since the energy varies directly as the square of the velocity, we can write:
E = kv^2
where k is a constant
Given: 600 kJ released when v = 5 m/s.  
Use this information to find k:
600 kJ = k(5 m/s)^2
k = 600/25 = 24 kJ*s^2/m^2
So, the energy released when v = 12 m/s is:
E = 24(12)^2 = 3456 kJ