Question 436202
(x-2)^2/9+(y-3)^2/36=1
y= -1/2x+4

the first equation needs to be written so that it has a y=
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Sub for y in the 1st eqn and multiply thru by 36
{{{4*(x-2)^2 + (-x/2 + 1)^2 = 36}}}
{{{4x^2 - 16x + 16 + x^2/4 - x + 1 = 36}}}
{{{16x^2 - 64x + 64 + x^2 - 4x + 4 = 144}}}
{{{17x^2 - 68x + 68 = 144}}}
{{{17x^2 - 68x - 76 = 0}}}
*[invoke solve_quadratic_equation 17,-68,-76]
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{{{x = 2 - 12sqrt(17)/17}}}
{{{y = 3 + 6sqrt(17)/17}}}
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{{{x = 2 + 12sqrt(17)/17}}}
{{{y = 3 - 6sqrt(17)/17}}}