Question 436178
The energy, E, released when an object is stopped varies directly as the square of its velocity, v. If an object releases 600kj of energy when stopped from a velocity of 5m/s. How much energy is released when it is stopped from a speed of 12m/s?
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E = kv^2
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Solve for "k" using "If an object releases 600kj of energy when stopped from a velocity of 5m/s".
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600 = k*5^2
k = 24
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Equation:
E = 24*v^2
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How much energy is released when it is stopped from a speed of 12m/s?
E = 24*12^2
E = 3456kj
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Cheers,
Stan H.
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