Question 436153
one leg x cm
other leg = x cm
hypotenuse = x+7

x^2+x^2=(x+7)^2
2x^2=x^2+14x+49
x^2-14x-49=0
Solve by quadratic formula
a=	1	b=	-14	c=	-49				
									
b^2-4ac=196+196						
b^2-4ac=392==>	sqrt(	392	)=19.8		
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}									
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}									
x1=(14+19.8)/	2				
x1=	16.9								
x2=(14-19.8)/2					
x2= -2.9								
Ignore negative value	
The legs are 16.9 cm
Hypotenuse = 23.9 cm