Question 436126
3 green 4C3 = 4
2 green 4C2 * 6C1 = 6*6 = 36
1 green 4C1 * 6C2 = 4*15= 60
0 green 6C3 = 20
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The wording of the problem is unclear. Above is the number of combinations for each event.
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Ed