Question 436087
solve the equation [0 0 -1] 
                   [3 x 0]
                   [2 0 3] = x 2
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[0+0+0-[-2x+0+0]] = x^2
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2x = x^2
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x^2-2x = 0
x(x-2) = 0
x = 0 or x = 2
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Cheers,
Stan H.
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