Question 435776
{{{ 24/(1+r)+32/(1+r)^2 -50 = 0 }}}
Multiply both sides by {{{ (1+r)^2 }}}
{{{ 24*(1+r) + 32 - 50*(1+r)^2 = 0 }}}
{{{ 24 + 24r + 32 - 50*(1 + 2r + r^2) = 0 }}}
{{{ 24 + 24r + 32 - 50 - 100r - 50r^2 = 0 }}}
{{{ -50r^2 - 76r + 6 = 0 }}}
{{{ -25r^2 - 38r + 3 = 0 }}}
Use quadratic equation to solve
{{{r = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a = -25}}}
{{{b = -38}}}
{{{c = 3}}}
{{{r = (-(-38) +- sqrt( (-38)^2-4*(-25)*3 ))/(2*(-25)) }}}
{{{r = ( 38 +- sqrt( ( 1444 + 300 ))/(-50)) }}}
You can finish and check for math errors.