Question 435760
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Hi
The length of a rectangle is 7 inches less than 3 times the width
Let x and (3x-7)represent the width and length respectively
Question states***
  x(3x-7) = 40in^2
   3x^2 -7x - 40 = 0
factoring
  (3x +8)(x-5)=0 Note:SUM of the outside terms(-15x) and the inside terms(8x) = -7x
  (3x +8)=0  |tossing out negative solution for length
   (x-5)=0  x = 5", the width.  the length is 8"   (3*5"-7")