Question 435694
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Hi
{{{(a^p)^q = a^(p*q)}}}
8^{7 x - 10} = ( 1/16 )^{2 x - 10}
(2^3)^{7x - 10} = (2^-4 )^{2x - 10}
 2^3{7x-10} = 2^-4{2x-10}
   3(7x-10) = -4(2x-10)
    21x - 30 = -8x + 40
       29x = 70
         x = 70/29 = 2.4138