Question 435599
Find the eqn of the circle:
The midpoint is the center, point C
Cx = (-2+6)/2 = 2
Cy = (-3+1)/2 = -1
Center @ (2,-1)
----------
The radius is the distance from C to either point
{{{r^2 = 4^2 + 2^2 = 20}}}
----------------
{{{(x-2)^2 + (y+1)^2 = 20}}} is the circle
It crosses the x-axis when y = 0
{{{x^2 - 4x + 4 + 1 = 20}}}
{{{x^2 - 4x - 15 = 0}}}
*[invoke solve_quadratic_equation 1,-4,-15]
------------
x = 2 +/- sqrt(19)