Question 435486
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Let *[tex \Large x] represent the length.  Then *[tex \Large x\ -\ 3] represets the width.  The area of a rectangle is the length times the width, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(x\ -\ 3)\ =\ 70]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 3x\ -\ 70\ =\ 0]


Solve for *[tex \Large x].  Discard the negative root (no such thing as negative length).  Calculate *[tex \Large x\ -\ 3]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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