Question 435435
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The *[tex \Large \frac{1}{6}] that know COBOL include the *[tex \Large \frac{1}{10}] that know both COBOL and FORTRAN.  So *[tex \Large \frac{1}{6}\ -\ \frac{1}{10}\ =\ \frac{5}{30}\ -\ \frac{3}{30}\ =\ \frac{2}{30}] is the fraction that ONLY knows COBOL.


The *[tex \Large \frac{3}{5}] that know FORTRAN include the *[tex \Large \frac{1}{10}] that know both COBOL and FORTRAN.  So *[tex \Large \frac{3}{5}\ -\ \frac{1}{10}\ =\ \frac{6}{10}\ -\ \frac{1}{10}\ =\ \frac{5}{10}] is the fraction that ONLY knows FORTRAN


The sum *[tex \Large \frac{2}{30}\ +\ \frac{1}{10}\ +\ \frac{5}{10}\ =\ \frac{20}{30}\ =\ \frac{2}{3}] is the fraction that knows one, the other, or both.  That means the fraction that knows neither is *[tex \Large 1\ -\ \frac{2}{3}\ =\ \frac{1}{3}]







John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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