Question 435382
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Let *[tex \Large x] represent the base.  Then *[tex \Large x\ -\ 6] must represent the height.  Base times height divided by 2 is the area, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x(x\ -\ 6)}{2}\ =\ 80]


Rearrange


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 6x\ -\ 160\ =\ 0]


Solve the quadratic and discard the negative root.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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