Question 435309
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Hi
tire's mileage is normally distributed with a mean of 47,900 miles and a standard deviation of 2,050 miles
*Note: {{{z = blue(x - mu)/blue(sigma)}}}  
 no more than 5 percent of the tires will have to be replaced...
then z = -1.6449
 x = -1.6449*2050 + 47900 = 44,528