Question 45264
{{{x^3 – 3x^2 + 4x – 12}}}


Group the first two together and take out a common factor of {{{x^2}}}.  Then from the last two, take out a common factor of 4:

{{{x^2(x-3) +4(x-3) }}}


Notice that there is now a common factor of (x-3).  Take out this common factor, and you have:
{{{(x-3)(x^2 +4) }}}


The sum of squares does not factor at this level, so this is the final answer.


R^2 at SCC