Question 435268
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept.  
Line Perpendicular to 2x-3y=9  and passing thru Pt(3,-5)
 2x - 3y = 9  Or y = (-2/3)x -3  slope m = (-2/3)
New Line 
  y = (3/2)x + b
 -5 = (3/2)*-2 + b
 -2 = b
 y = (3/2)x - 2 (Blue Line)
{{{drawing(300,300,   -6, 6, -6, 6, grid(1),
circle(3, -5,0.3),
circle(0, -2,0.3),
circle(0, -3,0.3),
graph( 300, 300, -6, 6, -6, 6,0,(-2/3)x -3,1.5x-2 ))}}}