<PRE><B>Question 45267</B>
If the x intercept is (2,0) and the y intercept is (0,3), then the slope is the rise over run, so
{{{m=(3-0)/(0-2) = -3/2}}}


The equation of the line is y=mx + b, where m=-3/2 and b is the y intercept which is 3.  Therefore, the equation of the line is {{{y=(-3/2)x+3}}}.


The graph looks like this (no extra charge!!):
{{{graph(300,300, -6,6, -6,6, -3x/2+3) }}}


R^2 at SCC</PRE>