Question 435039
Transform the equation {{{3x^2-42x+6y+147=0}}} in the standard form,

{{{(X-Xo)^2=4c(Y-Yo)}}},

{{{3(x^2-14x+49)+6y+147-3*49=0}}} => {{{3(x-7)^2=-6y}}} => {{{(x-7)^2=-2(y-0)}}}

From the last expression of the parabola,s equation we have: the vertex is the 
point (7, 0) and the focus will be the point: [4c=-2 => c=-1/2],(7, -1/2).

Done.