Question 45380
Not quite...the setup is like this
x^2 + (x + 1)^2 = 85
(the sum of the squares)
Now we get
x^2 + x^2 + 2x + 1 = 85
2x^2 + 2x - 84 = 0
x^2 + x - 42 = 0
(x + 7)(x - 6) = 0
and
x = -7 or x = 6
but they must be positive, hence your numbers are
6 and 7