<PRE><B>Question 434866</B>
AIRPLANES The angle of elevation to an airplane viewed from the control tower at an airport is 7°.
 The tower is 200 feet high and the pilot reports that the altitude is 5200 feet.
 How far away from the control tower is the airplane?
Round your answer to the nearest foot.
:
This distance (d) from tower will be the hypotenuse of a right triangle
The altitude is the side opposite the angle at the tower
The tower is 200&#39; high, therefore, the altitude above the tower. 5200 - 200 = 5000 ft
:
Use the sine of 7 degrees
sin(7) = {{{5000/d}}}
d = {{{5000/sin(7)}}}
d = 41,027.5 ft</PRE>