Question 434850
Twice the square of an integer is 
3 less than 7 times the integer. 
Find the integer.
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Equations:
2x^2 = 7x-3
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2x^2-7x+3 = 0
Factor:
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2x^2-6x-x+3 = 0
2x(x-3)-(x-3) = 0
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(x-3)(2x-1) = 0
x = 3 or x = 1/2
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Cheers,
Stan H.
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