Question 434679
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Solve the first equation for y in terms of x:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{8}{x}]


Then substitute this value of y into the other equation in place of y:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 3\left(\frac{8}{x}\right)\ +\ 8\ =\ 0]


Multiply both sides by x:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ +\ 8x\ +\ 24\ =\ 0]


But 64 - 192 < 0 so there are no real roots.  That is to say there is no solution to your system of equations.  If you graph the two equations, you will see that they do not intersect.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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