<PRE><B>Question 434557</B>
Please help me solve this question: write in standard form 3i105+5i73-2i119
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I assume those numbers after the i are exponents?
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3i^105 = 3*i^(4*26+1) = 3*(i^4)^26*i^1 = 3*1*i = 3i
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5i^73 = 5*(i^4)^18*i^1 = 5*1*i = 5i
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2i^119 = 2*(i^4)^29*i^3 = 2*1*(-i) = -2i
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Adding you get 0+6i
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Cheers,
Stan H.
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