Question 434221
{{{x^2+y^2=49}}}
{{{y^2-4x=49}}}
Rearrange it to
{{{x^2+y^2=49}}}
{{{-4x+y^2=49}}}
Multiply the 2nd eq by -1
{{{x^2+y^2=49}}}
{{{4x-y^2=-49}}}
------------------addition method eliminates y^2, we are left with:
x^2 + 4x = 0
Factor out x
x(x+4) = 0
Two solutions
x = 0
x + 4 = 0
x = -4
:
It's obvious that x = 0 will work, find y when x = -4
Replace x with - 4 in the 2nd original equation
-4(-4) + y^2 = 49
16 + y^2 = 49
y^2 = 49-16
y^2 = 33
y = {{{sqrt(33)}}}
:
You can check the solutions in the 1st original equation