Question 434239
From trigonometric identity {{{(Sinx)^2+(cosx)^2=1}}}, we find

{{{(cox)^2=1-(sinx)^2=1-(sqrt(5/7))^2=1-(5/7)=2/7}}}, and {{{cosx=sqrt(2/7)}}}.

To find tanx as you know {{{tanx=sinx/cosx=sqrt(5/7)/sqrt(2/7)=sqrt(5/2)}}}

While {{{cotanx=1/tanx=1/sqrt(5/2)=sqrt(2/5)}}}. on the same way you can find 

secx and cosecx.