Question 434196
if p(x) = (x+3)squared
and q(x) = 3-x
solve such that p(x) = q(x)
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{{{x+3)^2 = 3-x}}}
{{{x^2 + 6x + 9 = 3-x}}}
{{{x^2 + 7x + 6 = 0}}}
(x+1)*(x+6) = 0
x = -6, -1
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Those are the 2 values of x that make p(x) = q(x)