Question 434064
If you mean to solve the equation:{{{y^(1/25)+5*y^(1/5)=0}}}, we substitute

{{{y^(1/5)=x}}} and after solve:{{{x^2+5x=0}}}, factoring the left side we have:

{{{x(x+5)=0}}}, thus the roots are x=0 and x=-5. Substitute again to find y:

{{{y^(1/5)=-5}}} => {{{y=(-5)^5}}} and for {{{y^(1/5)=0}}}, the solution is 

the empty set.