Question 434018
Please help me to factor complete: {{{b^6 + 125}}}
I tried: {{{(b^3 + 5)(b^3 + 15b + 5)}}}
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It's the sum of 2 cubes.
{{{m^3 + n^3 = (m+n)*(m^2 - mn + n^2)}}}
= {{{(b^2)^3 + 5^3}}}
--> {{{(b^2 + 5)*(b^4 - 5b^2 + 25)}}}