Question 433948
Length(L), Width(W), Perimeter(P) and Area(A)

{{{L=W+2}}}, therefore {{{P=2(L+W)}}} where {{{P=44}}}
Therefore; {{{44=2(L+W)}}}
          opening the brackets
           {{{44=2L+2W}}}
       substituting {{{L=W+2}}} 
           {{{44=2(W+2)+2W}}} 
           {{{44=2W+4+2W}}}
         {{{44-4=2W+2W}}}
           {{{40=4W}}}
Thus, {{{W=10}}} and {{{L=W+2}}} will be {{{L=10+2}}}, {{{L=12}}}

Now the Area; {{{A=L*W}}}
              {{{A=12*10}}} which is equal to 120
Hence, the area of the rectangle is {{{120ft^2}}}