Question 45325
From your description of the problem, I am assuming the figure has 3 equal sides with 6 ft each and if the fourth side were completed it would have formed a square but instead there is an arc (semi-circle).

Perimeter:

For the arc, we will need to use the formula for the perimeter of a circle that is = 2 * pi * r and divide it by 2

where pi = 22/7 = 3.1428
and r = radius of the circle, in this case it is 3 ft

Thus the perimeter of the arc is 3.1428 * 3 = 9.4284
So the total perimeter = 6 times 3 + 9.4284 = 27.4284 ft


Area:

The total area of the figure will be the Area of the Square + Area of the semicircle

Area of square = 6 * 6 = 36 square ft

Area of circle = pi * r^2
Area of the semi-circle is area of circle divided by 2

Thus, area of the arc/semi-circle = 3.1428 * 3 * 3 / 2 = 14.1426 square ft.

Total area = 36 + 14.1426 = 50.1426 sq. ft

(If you have any questions about this solution you can ask me at tutmath@gmail.com)