Question 433657
{{{3a + b = 200}}}
{{{a = (200 - b)/3}}}


Since {{{a}}} has to be a positive integer then {{{200 - b}}} has to be a multiple of 3.

So {{{200-b}}} can be 3, 6, 9,...., 198.


Thus 66 solutions are possible.


P.S.: {{{a=b=0}}} cannot be a solution since both {{{a}}} and {{{b}}} has to be positive.