Question 433535
{{{(6i)/((3-5i))}}}
Assume they want you to rationalize the denominator
Multiply by the conjugate of the denominator over itself
{{{(6i)/((3-5i))}}} * {{{((3+5i))/((3+5i))}}} = {{{(18i + 30i^2)/(9 + 15i - 15i - 25i^2)}}} = {{{(18i + 30(-1))/(9 - 25(-1))}}} = {{{(18i - 30)/(9 +25)}}} = {{{(18i - 30)/34}}}
we can reduce the fractions to:
{{{(9i - 15)/17}}}