Question 433500
{{{ 4^x-2^x-12=0 }}}
={{{2^(2x)-2^x-12=0}}}
ley {{{y=2^x}}}

so we have:

{{{y^2-y-12=0}}}
={{{(y-4)(y+3)=0}}}

y=4,y=-3

since{{{y=2^x}}}
we need to solve {{{2^x=4}}} and {{{2^x=-3}}}


{{{2^x=-3}}} has no solutions so we look at {{{2^x=4}}}. here x=2