Question 433456
I cant finish these homework problems. The problem is set up as a rectangle with 6 columns down and 3 rows across. a is in the left corner and z is in the bottom right. b is located 2 columns across starting at a, one row down. C is located 3 columns across ad 2 rows down from a. 
a[][][][][][]
[][]b[][][][]
[][][]c[][][]z 
2. (1 point) If a route (with no backtracking) from A to Z is randomly chosen, what is the probability that the route passes through point B? Answer in fraction.----
# of routes from a to z: 2*3*4*5*6*5*4*3*2*1 = 6!*5! = 86400 
# of rountes from a to z thru b: 2*1*4*5*6*5*4*3*2*1 = 28800
P(a to z thru b) = 1/3 
Note: I'm assuming the "b" box is to the left of your letter "b".
If it's to the right the answer is 1/4
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3. (1 point) Given that a route passes through B, what is the probability that it also passes through point C? Answer in fraction.
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I'll leave the counting to you:
P(B|C| = P(B and C)/P(C)
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Cheers,
Stan H.
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