Question 433328
"Use the discriminant to determine how many real-number solutions the equation has.
 1 - 7a2 = -7a - 2"


Discriminant is b² - 4ac
If b² - 4ac > 0, there are two real number solutions
If b² - 4ac = 0, there is one real number solution
If b² - 4ac < 0, there are two imaginary number solutions


1 - 7a² = -7a - 2
7a² - 7a - 3 = 0 {added 7a² and subtracted 1 from both sides}
a = 7, b = -7, c = -3


b² - 4ac
= (-7)² - 4(7)(-3)
= 49 + 84
= 133


133 > 0,there are two real number solutions
<a href = "http://www.algebrahouse.com/" target = "_blank">www.algebrahouse.com</a>