Question 433316
 e^x +3lnx-15=0 can be solved for x? 
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3ln(x) = 15-e^x
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ln(x) = 5-(1/3)e^x
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ln(x) = 5-e^(-3x)
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Graph the two sides on the same set of coordinate axes.
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{{{graph(400,300,-10,200,-10,10,ln(x),5-(2.71828)^(-3x))}}}
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x=148.41316
Cheers,
Stan H.