<PRE><B>Question 45234</B>
A circle with center at (h,k) and radius r is given by 
{{{ (x-h)^2 + (y-k)^2 = r^2 }}}


Therefore if the center is at (0,2) and radius = {{{sqrt(14)}}}, then {{{r^2= 14}}}, and the equation will be{{{(x-0)^2 + (y+2)^2 = 14}}}.


In case they want you to multiply this out, it would be
{{{x^2 + y^2+4y+4 -14= 0}}}
{{{x^2 +y^2 +4y -10= 0}}}


R^2 at SCC</PRE>