Question 433151
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If the towns are 480 km apart, by the time the two cars meet, a total of 480 km will have been traversed, part by one car and another part by the other car.  If the time to the meeting is 3 hours, then the SUM of the two cars' speeds must be 480 divided by 3, or 160 km/hr.  If you let *[tex \Large x] represent the speed of the faster car, then *[tex \Large x - 20] must represent the speed of the slower car, and since the sum of their speeds is 160, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ -\ 20\ =\ 160]


Solve for *[tex \Large x].  Don't forget to express your answer in km/hr.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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