Question 433138
Perimeter of rectangle=2L+2W=268
L=W+64
Substitute W+64 in for L in the perimeter equation
{{{2(W+64)+2W=268}}} Simplify and solve
{{{2W+128+2W=268}}}
{{{4W+128=268}}}
{{{4W=140}}}
{{{W=35}}}
Since the length exceeds the width by 64, {{{L=35+64=99}}}