Question 433137
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept.  
perpendicular to 3x+4y=12 and passes through (7,1)?
3x+4y=12  y= (-3/4)x + 3 ( m = (-3/4))
NEw Line: Perpendicular Line will have slope that is the negative reciprocal,
 y = (4/3)x + b   |Using ordered pair (7,1) to solve for b
 1 = (4/3)*7 + b  
 -25/3 = b 
  y = (4/3)*x - 25/3
 {{{drawing(300,300,  -15,15,-15,15, grid(1),
circle(7, 1,0.6),
graph( 300, 300,-15,15,-15,15,0,(4/3)*x - 25/3
))}}}