Question 433133
This is a system of equations
One equation involves the number of coins:
n + p = 12
The involves the total value:
.05n + .01p = .32
Solve the first equation for either variable, we'll choose n.
{{{n+p=12}}}
{{{n=12-p}}}
Then take 12-p and substitute it in for n in the second equation.
{{{.05(12-p)+.01p=.32}}}
Then solve for p.
{{{.60-.05p+.01p=.32}}}
{{{.60-.04p=.32}}}
{{{-.04p=-.28}}}
{{{p=7}}} So there are 7 pennies. This leaves 5 nickels.